Common ratio and progressions puzzle


An arithmetic progression (AP) is a sequence of numbers with a common difference between them, e.g. 3, 7, 11, 15, …

A geometric progression (GP) is a sequence of numbers with a common ratio between them, e.g. 2, 6, 18, 54, …

If the 1st, 2nd and 6th terms of an AP form a GP what is the common ratio?

If the 1st, 2nd and nth terms of an AP form a GP what is the common ratio?

Reveal Solution
The 1st, 2nd, and 6th terms of an AP are a, a + d, a +5d

These three terms forming a GP gives: \frac{a + d}{a}=\frac{a + 5d}{a+d}

Rearranging this gives:

a^2 +2ad +d^2 = a^2 +5ad

2ad +d^2 = 5ad

d^2 = 3ad

d = 3a

(or d= 0 which isn’t very interesting)

Therefore the GP has first two terms a, 4a and hence the common ratio is 4.

Similarly, the 1st, 2nd and nth terms of an AP are a, a+d, a+(n-1)d

This gives d=(n-3)a and hence a common ratio of n-2

Problem Page Coordinator: Stephen Lee CMath MIMA – Mathematics in Education and Industry
Acknowledgement: The IMA are indebted to MEI for sourcing and supplying Mathematics Today with these well-known puzzles.
First published in Mathematics Today (December 2015)
Published